Integrand size = 35, antiderivative size = 110 \[ \int \left (-\frac {b \cos \left (a+b x-c x^2\right )}{x}+\frac {\sin \left (a+b x-c x^2\right )}{x^2}\right ) \, dx=\sqrt {c} \sqrt {2 \pi } \cos \left (a+\frac {b^2}{4 c}\right ) \operatorname {FresnelC}\left (\frac {b-2 c x}{\sqrt {c} \sqrt {2 \pi }}\right )+\sqrt {c} \sqrt {2 \pi } \operatorname {FresnelS}\left (\frac {b-2 c x}{\sqrt {c} \sqrt {2 \pi }}\right ) \sin \left (a+\frac {b^2}{4 c}\right )-\frac {\sin \left (a+b x-c x^2\right )}{x} \]
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Time = 0.06 (sec) , antiderivative size = 110, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.114, Rules used = {3546, 3529, 3433, 3432} \[ \int \left (-\frac {b \cos \left (a+b x-c x^2\right )}{x}+\frac {\sin \left (a+b x-c x^2\right )}{x^2}\right ) \, dx=\sqrt {2 \pi } \sqrt {c} \cos \left (a+\frac {b^2}{4 c}\right ) \operatorname {FresnelC}\left (\frac {b-2 c x}{\sqrt {c} \sqrt {2 \pi }}\right )+\sqrt {2 \pi } \sqrt {c} \sin \left (a+\frac {b^2}{4 c}\right ) \operatorname {FresnelS}\left (\frac {b-2 c x}{\sqrt {c} \sqrt {2 \pi }}\right )-\frac {\sin \left (a+b x-c x^2\right )}{x} \]
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Rule 3432
Rule 3433
Rule 3529
Rule 3546
Rubi steps \begin{align*} \text {integral}& = -\left (b \int \frac {\cos \left (a+b x-c x^2\right )}{x} \, dx\right )+\int \frac {\sin \left (a+b x-c x^2\right )}{x^2} \, dx \\ & = -\frac {\sin \left (a+b x-c x^2\right )}{x}-(2 c) \int \cos \left (a+b x-c x^2\right ) \, dx \\ & = -\frac {\sin \left (a+b x-c x^2\right )}{x}-\left (2 c \cos \left (a+\frac {b^2}{4 c}\right )\right ) \int \cos \left (\frac {(b-2 c x)^2}{4 c}\right ) \, dx-\left (2 c \sin \left (a+\frac {b^2}{4 c}\right )\right ) \int \sin \left (\frac {(b-2 c x)^2}{4 c}\right ) \, dx \\ & = \sqrt {c} \sqrt {2 \pi } \cos \left (a+\frac {b^2}{4 c}\right ) \operatorname {FresnelC}\left (\frac {b-2 c x}{\sqrt {c} \sqrt {2 \pi }}\right )+\sqrt {c} \sqrt {2 \pi } \operatorname {FresnelS}\left (\frac {b-2 c x}{\sqrt {c} \sqrt {2 \pi }}\right ) \sin \left (a+\frac {b^2}{4 c}\right )-\frac {\sin \left (a+b x-c x^2\right )}{x} \\ \end{align*}
Time = 0.51 (sec) , antiderivative size = 115, normalized size of antiderivative = 1.05 \[ \int \left (-\frac {b \cos \left (a+b x-c x^2\right )}{x}+\frac {\sin \left (a+b x-c x^2\right )}{x^2}\right ) \, dx=-\frac {\sqrt {c} \sqrt {2 \pi } x \cos \left (a+\frac {b^2}{4 c}\right ) \operatorname {FresnelC}\left (\frac {-b+2 c x}{\sqrt {c} \sqrt {2 \pi }}\right )+\sqrt {c} \sqrt {2 \pi } x \operatorname {FresnelS}\left (\frac {-b+2 c x}{\sqrt {c} \sqrt {2 \pi }}\right ) \sin \left (a+\frac {b^2}{4 c}\right )+\sin (a+x (b-c x))}{x} \]
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\[\int \left (-\frac {b \cos \left (-c \,x^{2}+b x +a \right )}{x}+\frac {\sin \left (-c \,x^{2}+b x +a \right )}{x^{2}}\right )d x\]
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none
Time = 0.30 (sec) , antiderivative size = 124, normalized size of antiderivative = 1.13 \[ \int \left (-\frac {b \cos \left (a+b x-c x^2\right )}{x}+\frac {\sin \left (a+b x-c x^2\right )}{x^2}\right ) \, dx=-\frac {\sqrt {2} \pi x \sqrt {\frac {c}{\pi }} \cos \left (\frac {b^{2} + 4 \, a c}{4 \, c}\right ) \operatorname {C}\left (\frac {\sqrt {2} {\left (2 \, c x - b\right )} \sqrt {\frac {c}{\pi }}}{2 \, c}\right ) + \sqrt {2} \pi x \sqrt {\frac {c}{\pi }} \operatorname {S}\left (\frac {\sqrt {2} {\left (2 \, c x - b\right )} \sqrt {\frac {c}{\pi }}}{2 \, c}\right ) \sin \left (\frac {b^{2} + 4 \, a c}{4 \, c}\right ) - \sin \left (c x^{2} - b x - a\right )}{x} \]
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\[ \int \left (-\frac {b \cos \left (a+b x-c x^2\right )}{x}+\frac {\sin \left (a+b x-c x^2\right )}{x^2}\right ) \, dx=- \int \left (- \frac {\sin {\left (a + b x - c x^{2} \right )}}{x^{2}}\right )\, dx - \int \frac {b \cos {\left (a + b x - c x^{2} \right )}}{x}\, dx \]
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\[ \int \left (-\frac {b \cos \left (a+b x-c x^2\right )}{x}+\frac {\sin \left (a+b x-c x^2\right )}{x^2}\right ) \, dx=\int { -\frac {b \cos \left (-c x^{2} + b x + a\right )}{x} + \frac {\sin \left (-c x^{2} + b x + a\right )}{x^{2}} \,d x } \]
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\[ \int \left (-\frac {b \cos \left (a+b x-c x^2\right )}{x}+\frac {\sin \left (a+b x-c x^2\right )}{x^2}\right ) \, dx=\int { -\frac {b \cos \left (-c x^{2} + b x + a\right )}{x} + \frac {\sin \left (-c x^{2} + b x + a\right )}{x^{2}} \,d x } \]
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Timed out. \[ \int \left (-\frac {b \cos \left (a+b x-c x^2\right )}{x}+\frac {\sin \left (a+b x-c x^2\right )}{x^2}\right ) \, dx=\int \frac {\sin \left (-c\,x^2+b\,x+a\right )}{x^2}-\frac {b\,\cos \left (-c\,x^2+b\,x+a\right )}{x} \,d x \]
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